dexlessmalyk
Name : (specify a nickname) IGN : TimesEye Job : Sniper Level : 104 Number of posts : 38 Registration date : 2008-05-13
| Subject: Geometric Sequence ????????????? Tue Sep 16, 2008 4:08 pm | |
| I know the formula is a n=a 1r n-1but in order to do that u need a ratio(r) and a first term (a 1) and i have term 3 and tem 6 they were given to me in the problem a 3= 180, a 6=38,880 i need to find the ratio and the 1st term | |
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SpikeAi
Name : Neal IGN : SpikeAi Job : Bow Master Level : 151 Number of posts : 737 Registration date : 2008-04-21
| Subject: Re: Geometric Sequence ????????????? Tue Sep 16, 2008 5:01 pm | |
| Uhh not sure if you will understand my logic or if it is what the teacher wants to see..
between a3 and a6 there are 3 multiplications all by the same value x.
Therefore 180 * x * x * x = 38880 Or 180* x^3 = 38880
x^3 = 38880/180 x^3 = 216 x = cube root of 216 x = 6 | |
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Loveable Kaze
Name : David IGN : Kazegenso (retired) Job : Writer Level : up! =D Number of posts : 1208 Registration date : 2007-06-19 Mood : Speechless!
| Subject: Re: Geometric Sequence ????????????? Tue Sep 16, 2008 5:24 pm | |
| I never learned this in my Geometry class....o_O" It's quite interesting... | |
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Bilbo Administrator
Name : Daniel IGN : Bersy Job : Dark Knight Level : 200 Number of posts : 1820 Registration date : 2008-03-20 Mood : pretending to be a Hobbit
| Subject: Re: Geometric Sequence ????????????? Wed Sep 17, 2008 1:00 am | |
| use the formula and make two equations with two unknowns, a1 and r: 180 = a1 * r2 (squared) a1 = 180/r2 substitute in 2nd equation: 38,880 = a1 * r5 (power 5) 38,880 = 180/r2 * r5 38,888 = 180 * r3 r3 = 38,880/180 = 216 r = 6 a1 = 180/36 = 5 | |
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| Subject: Re: Geometric Sequence ????????????? | |
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